CBSE Class 12 Board Paper 2025 Solved — Section A (Part 1)
Full solutions to Section A of the CBSE Class 12 Board Paper 2025, explained by Saurabh Sir.
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JEE Advanced 2014 Question Explained Step-by-Step
Saurabh Sir explains a past JEE Advanced question in detail, useful for students preparing for competitive exams alongside CBSE boards.
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Finding the Minimum Value of x² + y² — Advanced Problem Solved
A tricky algebra problem broken down step by step — finding the minimum value of x² + y² given a transcendental relation.
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3D Geometry — Long Answer Questions Solved (Part 1) | Class 12 CBSE
Kavita Maam solves long-answer 3D Geometry questions commonly asked in the CBSE Class 12 board exam.
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CBSE Sample Paper PYQs Solved — Section C, D & E (Part 3)
Saurabh Sir covers Sections C, D, and E of the sample paper in full detail. Free practice paper download link included in the video. Category:
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CBSE Sample Paper PYQs Solved — Section A (Part 2)
A detailed walkthrough of Section A previous year questions from the CBSE sample paper, explained by Saurabh Sir.
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CBSE Sample Paper PYQs Solved — Section B (Part 1)
Saurabh Sir walks through previous year sample paper questions from Section B, step by step — ideal for CBSE board exam revision.
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Important Board Exams Instructions (Year 2023-24)
Hi students. Sharing some important information for your Board Exams
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Synthetic Division Lesson 1
Hi students! In this video I am explaining synthetic Division of Polynomials. Synthetic division is a technique to divide a polynomial with a linear binomial by only considering the values of the coefficients. Here are the steps involved in synthetic division: Write down the coefficients of the dividend (the polynomial being divided) in descending order of degree, with the coefficient of the highest degree term in the leftmost column. If a coefficient is missing, add a zero in its place. Write down the divisor (the polynomial dividing into the dividend) to the left of the table, with its coefficient negative. Bring down the leading coefficient of the dividend (the one in the leftmost column) to the bottom of the table. Multiply that number by the divisor’s coefficient and write the product in the next column. Add the number in the second column to the next coefficient of the dividend and write the sum in the bottom of the second column. Repeat steps 4 and 5 for each coefficient of the dividend until you reach the constant term. The last number in the bottom row is the remainder. The other numbers in the bottom row, read from left to right, are the coefficients of the quotient, in descending order of degree.
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